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If 7.25 kJ of heat is applied to a 980 gram block of metal and the temperature started at 25C and finished at 36 C. What is the specific heat of the metal in J/g C

Respuesta :

J=mc(t2-t1)
7250=980C(36-25). Convert kj-j immediately so units make sense at the end.
7250=10780C
C= .673 J/g