Answer:
Wavelength of light is 608 nm.
Explanation:
It is given that,
Distance associated with the fringes, d = 0.14 mm = 0.00014 m
Number of fringes, m = 460
We need to find the wavelength of the light. In Michelson interferometer, the distance associated with the fringes is given by :
[tex]d=\dfrac{m\lambda}{2}[/tex]
[tex]\lambda=\dfrac{2d}{m}[/tex]
[tex]\lambda=\dfrac{2\times 0.00014 }{460}[/tex]
[tex]\lambda=6.08\times 10^{-7}\ m[/tex]
[tex]\lambda=608\ nm[/tex]
So, the wavelength of the light is 608 nm. Hence, this is the required solution.
