Respuesta :
Answer:
The star, Alpha Crucis, is brighter than the star, Alpha Centauri, when observed from Earth
Explanation:
The given parameters are;
The apparent magnitude of the star Alpha Centauri = -0.27
The apparent magnitude of the star Alpha Crucis = 0.77
Let relative brightness of two stars is given by the relation
[tex]\dfrac{b_1}{b_2} = 2.512^{(m_1 - m_2)}[/tex]
Where;
m₁ = The apparent magnitude of the star Alpha Centauri = -0.27
m₂ = The apparent magnitude of the star Alpha Crucis = 0.77
b₁ = The brightness of the star Alpha Centauri
b₂ = The brightness of the star Alpha Crucis
Which gives;
[tex]\dfrac{b_1}{b_2} = 2.512^{(-0.27 - 0.77)}= 0.383689[/tex]
Therefore;
b₁/b₂ = 0.383689 and
b₁ = b₂ × 0.383689
b₂ = b₁/0.383689 = 2.606×b₁
b₂ = 2.606×b₁
b₂ > b₁, b₂ is brighter than b₁, that is the star, Alpha Crucis is brighter than the star, Alpha Centauri, when observed from Earth.
