Which of the following is the equation of the line that has a slope of negative three and passes through the point begin ordered pair, negative 2, 6, end ordered pair?

A
begin equation . . . Y equals, negative 3 times X . . . end equation

B
begin equation . . . Y equals, negative 3 times X, minus 4 . . . end equation

C
begin equation . . . Y equals, negative 3 times X, plus 8 . . . end equation

D
begin equation . . . Y equals, negative 3 times X, plus 16 . . . end equation

Respuesta :

The answer would be A)

Explanation:
If you plug in the numbers 6= -3(-2)
That would equal 6 = 6

The equation that ishaving slope of -3 and passes through (-2,6) is y=-3x which is option a.

What is equation?

Equation is relationship between two or more variables expressed in equal to form. Equation of two variables look like ax+by=c and standard form of equation is y=mx+c in which m is the slope of line whose equation is found.

How to form equation?

We have been given slope of line equal to -3 and point through which line passes being (-2,6) and we are required to find the equation of line.

As said earlier standard form is y=mx+c in which m is slope and equation is formed from the formula which is as under:

[tex](y-x_{1})=m(x-x_{1})[/tex]

putting the values in the above formula we get:

(y-6)=-3[x-(-2)]

y-6=-3(x+2)

y-6=-3x-6

y=-3x-6+6

y=-3x.

Hence the equation having slope -3 and passes  through point (-2,6) is y=-3x.

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