contestada

How many moles of gas were added to a balloon that started with 2.3 moles of gas and a volume of 1.4 l given that the final volume was 7.2 l?
a.12
b.0.085
c.4.4
d.9.5
e.none of the above?

Respuesta :

Kalahira
Ideal Gas Law is as follows: PV = nRT Now lets rearrange so we can get rid of some variables. V/n = RT/P Assuming temperature and pressure are the same (atmospheric pressure), we can get: PV/n = constant (k) Now since we are dealing with an initial state (2.3 moles, 1.4 liters) lets set that as V1 and n1 and the final state as V2 and n2 .V1/n1 = constant (k) V2/n2 = constant (k) Because the constant is the same (remember me making the assumptions above??) V1/n1 = V2/n2 now rearrangement: n1/V1/V2 = 1/n2 -1 = n2 Answer: 11.8 moles are in the final vessel. So to answer the question how much was ADDED, we need to subtract the initial mole number. 11.8 - 2.3 mols = 9.5 mols added

The number of moles of gas were added to a balloon that started with 2.3 moles of gas and a volume increases from 1.4L to 7.2L is 11.82 moles.

How do we calculate moles?

Number of moles of any gas will be calculated by uisng the ideal gas equation PV = nRT, for the given question equation becomes as:

V₁/n₁ = V₂/n₂, where

V₁ = initial volume = 1.4L

n₁ = initial moles = 2.3mol

V₂ = final volume = 7.2L

n₂ = final moles = ?

On putting values, we get

n₂ = (7.2)(2.3) / (1.4) = 11.82 moles

Hence required moles of gas is 11.82 mol.

To know more about ideal gas equation, visit the below link:
https://brainly.com/question/15046679

#SPJ3

Otras preguntas