Answer:
Difference in area = 75 ft²
Step-by-step explanation:
Case 1 (When logan had only one dog):
length of the play space= [tex]12[/tex] ft
breadth of the play space= [tex]10[/tex] ft
we know that area of a rectangle is length times breadth (length x breadth)
therefore, area of the play space= [tex]12*10[/tex]
=[tex]120ft^{2}[/tex]
Case 2(When Logan had two dogs):
Given: Logan wants to increase the length of the play space by 3 feet and width by 3 feet
⇒length of the play space= [tex]12+3[/tex] ft=[tex]15[/tex] ft
breadth of the play space=[tex]10+3[/tex] ft=[tex]13[/tex] ft
we know that area of a rectangle is length times breadth (length x breadth)
therefore, area of the play space= [tex]15*13[/tex]
=[tex]195ft^{2}[/tex]
Therefore difference in the area of play space = [tex]195-120[/tex]
=75 ft²
