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 A hotdog cannon shoots a hotdog straight up in the air with an initial velocity of 30 m/s. How high will the hotdog fly?

Respuesta :

LammettHash

At its peak height, the hotdog will have no vertical velocity, so that

[tex]{v_f}^2-{v_i}^2=2(-g)\Delta y\implies-\left(30\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)y_{\mathrm{max}}[/tex]

[tex]\implies y_{\mathrm{max}}=46\,\mathrm m[/tex]

okpalawalter8

We have that for the Question " A hotdog cannon shoots a hotdog straight up in the air with an initial velocity of 30 m/s. How high will the hotdog fly?" it can be said that How high  the hotdog will fly is

s=45.91m

From the question we are told

A hotdog cannon shoots a hotdog straight up in the air with an initial velocity of 30 m/s. How high will the hotdog fly?

Generally the Newtons equation for the distance is mathematically given as

v^2=2as

Therefore

v^2=2as

30^2=2*9.8*s

s=\frac{30^2}{2*9.8}

s=45.91m

Therefore

How high  the hotdog will fly is

s=45.91m

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https://brainly.com/question/19007362

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