gabygon2313
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If an object is propelled from ground level, the maximum height that it reaches is given by h = v2 sin2 θ , where θ is the angle between the ground 2g and the initial path of the object, v is the object’s initial velocity, and g is the acceleration due to gravity, 9.8 meters per second squared.

Respuesta :

heon1219

Answer:

Answer is D, 598.7m

Step-by-step explanation:

The problem literally tells you what number to put in to the equation.

(110^2 * sin^2theta )/(2*9.8)

put this in to a scientific calc, and you get 598.731650804.

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abiolataiwo2015

The  maximum height of the rocket if  a model rocket is launched with an initial velocity of 110 meters per second at an angle 80 ° is: 598.7 meters.

Maximum height

Given:

Maximum height=h = v2 sin2 θ

Where:

θ =angle between the ground and the initial path of the object

v = object’s initial velocity

g= acceleration due to gravity,

Hence:

Maximum height=(110² ×sin²80 )/(2×9.8)

Maximum height=(110² ×sin²80 )/19.6

Maximum height=598.7 meters

Therefore the maximum height is 598.7 meters.

Learn more about maximum height here:https://brainly.com/question/12446886

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