Answer:
[tex]D.\ \angle FOB\ and\ \angle EOC[/tex]
Step-by-step explanation:
[tex]\angle FOC=180\textdegree\ \ \ \ \ \ \ \ \ \ as\ FOC\ is\ a\ straight\ line\\\\\angle FOC=\angle COE+\angle EOF\\\\\angle COE+\angle EOF=180\textdegree\\\\Hence\ \angle COE\ is\ supplementary\ to\ \angle EOF[/tex]
[tex]\angle EOB=180\textdegree\ \ \ \ \ \ \ \ \ \ as\ EOB\ is\ a\ straight\ line\\\\\angle EOB=\angle FOB+\angle EOF\\\\\angle FOB+\angle EOF=180\textdegree\\\\Hence\ \angle FOB\ is\ supplementary\ to\ \angle EOF[/tex]
