For this case suppose we have a function of the form:
y = f (x)
Where,
x: independent variable
y: dependent variable
We have then that the value of the function for x = c is:
f (c) = 0
Therefore, we have that:
The point (c, 0) belongs to f (x)
x-c is a common factor of f (x) because the function evaluated at x = c is equal to zero.
x = c is a root of f (x) so c is a zero of the function f (x)
Answer:
D. All three statements are true.
