Respuesta :
To maximize the amount of fencing to create the biggest area possible, you will want to create a quadrilateral as close to or equal to a square as possible.
In this case, 112 is evenly divisible by 4 to give you sides lengths of 28.
The area would be 28 feet x 28 feet.
28 x 28 = 784 square feet of area.
All Squares are rectangles.
In this case, 112 is evenly divisible by 4 to give you sides lengths of 28.
The area would be 28 feet x 28 feet.
28 x 28 = 784 square feet of area.
All Squares are rectangles.