First, write a balanced chemical equation:
2H2(g) + O2(g) --> 2H2O(l)
We are given that oxygen has a volume of 3.84L, so we need to use the formula n = V / MV
As mentioned, at stp, so MV= 24.79
n = 3.84 / 24.79
= 0.1549...
The ratio of oxygen to water is 1:2, therefore we need to multiply the moles found by 2 to gain the moles of water,
n = 0.1549... x 2
= 0.3098...
Use the formula n = m / M, where m is mass and M is molar mass
0.3098.. = m / (2(1.008) + 2(16))
m = 0.3098... x (2(1.008) + 2(16))
= 10.538...
Therefore, 10.54g of water is produced (2 d.p)
HOPE THIS HELPED!
