In the figure below, a cone is cut by a plane that passes through its vertex and is perpendicular to its base.

The height of the cone is 10 inches, and its diameter is 6 inches.

What is the area of the cross section formed by the intersection?

In the figure below a cone is cut by a plane that passes through its vertex and is perpendicular to its base The height of the cone is 10 inches and its diamete class=

Respuesta :

When a cone is cut by a plane that passes through its vertex and perpendicular to its base the figure formed is an isosceles triangle.It is given the height of the cone is 10 inches, and its diameter is 6 inches.

The height of the cone will be the height of the triangle .The diameter of the cone will be the base of the triangle.Base and height of the triangle known we can find the area of cross section or the area of the triangle by the formula

Area = [tex] \frac{1}{2} Base .Height. [/tex]

Area = [tex] \frac{1}{2} (10)(6)=30 in^{2} [/tex]