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Kalahira
12240 lbm/h
   This problem is using the units of lb-mole (the number of atoms in 12 lbs of carbon) and lbm (pounds mass). This requires a small conversion factor of 0.999109128 to be applied to the atomic weights to convert from grams/mole to get lb-mole for each element.
  The formula for propyl acetate is C5H10O2. So let's first calculate the molar mass of C5H10O2 by looking up their atomic weights.
 atomic weight carbon = 12.0107 * 0.999109128 = 12
 atomic weight hydrogen = 1.00794 * 0.999109128 = 1.007
 atomic weight oxygen = 15.999 * * 0.999109128 = 15.985
   Molar mass C5H10O2 = 5 * 12 + 10 * 1.007 + 2 * 15.985 = 102.04 lbm/lb-mol
   Now let's get the mass 102.04 lbm/lb-mol * 120.0 lb-mol/h = 12244.8 lbm/h
   Rounding to 4 significant figures gives 12240 lbm/h
sebassandin

Answer:

[tex]1.226x10^{4}\frac{lbm}{h}[/tex]

Explanation:

Hello,

In this case, the following mole-mass relationship is used to convert from lb-mole to lbm of propyl acetate, considering its molar mass of 102.131lbm/lb-mol (structure on the attached picture):

[tex]120.0\frac{lb-mole}{h}*\frac{102.131lbm}{1lb-mole}=1.226x10^{4}\frac{lbm}{h}[/tex]

Best regards.

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