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1. picture
2.picture
3.which graph represents f(x)=4sin(2πx)?
4. A cosine function has a period of 3, a maximum value of 20, and a minimum value of 0. The function is a reflection of its parent function over the x-axis.
Which function could be the function described?

5. A sinusoidal function whose frequency is 3, maximum value is 15, minimum value is −3 has a y-intercept of 6.
Which function could be the function described?
f(x)=9sin(6πx)+3
f(x)=9sin(3x)+3
f(x)=9sin(x3)+6
f(x)=9sin(6πx)+6

1 picture 2picture 3which graph represents fx4sin2πx 4 A cosine function has a period of 3 a maximum value of 20 and a minimum value of 0 The function is a refl class=
1 picture 2picture 3which graph represents fx4sin2πx 4 A cosine function has a period of 3 a maximum value of 20 and a minimum value of 0 The function is a refl class=
1 picture 2picture 3which graph represents fx4sin2πx 4 A cosine function has a period of 3 a maximum value of 20 and a minimum value of 0 The function is a refl class=
1 picture 2picture 3which graph represents fx4sin2πx 4 A cosine function has a period of 3 a maximum value of 20 and a minimum value of 0 The function is a refl class=

Respuesta :

Problem 1

See the attached image. Specifically see figure 1.

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Problem 2

See the attached image. Specifically see figure 2.

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Problem 3

Answer: bottom right corner

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f(x) = 4*sin(2pi*x)
f(x) = a*sin(b*x)
a = 4 is the amplitude
b = 2pi
T = 2pi/b = 2pi/2pi = 1 is the period

The graph that has a period of 1 and amplitude 4 is the bottom row of choices. We can rule out the graph on the left because sine starts off increasing as you move away from the origin and go from left to right. 

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Problem 4

Answer: f(x) = -10cos(2pi*x/3)

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T = period = 3
b = 2pi/T = 2pi/3
amplitude = (max - min)/2
amplitude = (20-0)/2
amplitude = 10
y = 10 is the midline since d = (20+0)/2 = 10

f(x) = a*cos(bx)+d
f(x) = -10*cos(2pi*x/3)+10

Note: the value of 'a' is negative because of the reflection over the x axis
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Problem 5

Answer: Choice D
f(x) = 9*sin(6pi*x)+6

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min = -3
max = 15
midline: d = (max + min)/2 = (15-3)/2 = 6
amplitude: a = (max - min)/2 = (15+3)/2 = 9
f = frequency = 3
T = period = 1/f = 1/3
b = 2pi/T = 2pi/(1/3) = 6pi

f(x) = a*sin(bx)+d
f(x) = 9*sin(6pi*x)+6

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Ver imagen jimthompson5910
Ver imagen jimthompson5910

The graph is shown in the figures.

Sinusoidal function

It is a function that repeats itself after a regular interval of time.

How to calculate?

1.  Graph of g(t) = 4sin(3t) + 2 is shown below.

2.  Graph of f(x) = 3cos(2x) - 1 is shown below.

3.  Graph D represents the f(x) = 4sin(2[tex]\rm \pi[/tex]x) because the value of sine maximum and the minimum are 1 and -1 so the value of f(x) is maximum and the minimum is 4 and -4.

4.  The maximum and minimum value of f(x) 20 and 0. and period is 3. then our f(x) will be

[tex]f(x) = 10\ cos(\dfrac{2\pi }{3}x ) +10[/tex]

5.  For this D is the correct option. because maximum and minimum values, as well as frequency, satisfy the equation.

Thus, the graph is shown in figures.

More about the sinusoidal function link is given below.

https://brainly.com/question/12078395

Ver imagen jainveenamrata
Ver imagen jainveenamrata

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