Respuesta :

mathmate
For given Poisson distribution, μ=0.5, and k=x=4

[tex]P(k)=\frac{\mu^ke^{-\mu}}{k!}[/tex]
so
[tex]P(4)=\frac{0.5^4e^{-0.5}}{4!}[/tex]
[tex]=0.0015795[/tex] approx.
abidemiokin

The probability that x=4​ is x has a poisson distribution with μ=0 is 0.0015795

Poisson probability

The formula for calculating the poisson probability is expressed as shown below:

[tex]P(x) = \frac{\mu^xe^{-\mu}}{x!}[/tex]

Given the following parameters

μ=0.5​,

x = 4

Substitute

[tex]P(x) = \frac{0.5^4e^{-0.5}}{4!}\\P(x)=0.0015795[/tex]

Hence the probability that x=4​ is x has a poisson distribution with μ=0 is 0.0015795

Learn more on poisson probability here; https://brainly.com/question/9123296

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