Two fruit flies that are heterozygous for body color and eye color are crossed. Brown body color is dominant to black body color. Red eye color is dominant to brown eye color. Use the Punnett square to determine the ratio of offspring with: Brown body and red eyes : Brown body and brown eyes : Black body and red eyes : Black body and brown eyes :

In a double cross of two heterozygotes for both traits ( BrBl Rbx BrBl Rb) we would get a 9:3:3:1 phenotypic ratio.
9 Brown body, red eyes (both dominant traits)
3 brown body, brown eyes (one dominant, one recessive trait)
3 black body, red eyes ( one recessive and one dominant trait)
1 black body, brown eyes ( both recessive traits)

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kasliwalalvi24 kasliwalalvi24 · Answer 2 · 2021-11-09T05:34:18+01:00

Heterozygous pair of genes refer to the inheritance of different forms of a particular gene. The dihybrid cross between heterozygous genotypes will result in the ratio of 9:3:3:1.

The number of offspring with a different genotype are:

9 Brown body, red eyes (both dominant traits)

3 brown body, brown eyes (one dominant, one recessive trait)

3 black body, red eyes ( one recessive and one dominant trait)

1 black body, brown eyes ( both recessive traits)

The dihybrid cross between heterozygous traits will be:

The heterozygous cross between Brown fur {BB} and black fur (bb) with red-eye (RR) and brown eye (rr) will be calculated by Punnet square.

The punnet square for the cross BbRr x BbRr will result in the ratio of 9:3:3:1.

Since brown fur and red eye are dominant, therefore they will be expressed in the heterozygous condition.

Therefore, the ratio for dihybrid cross is 9:3:3:1.

To know more about dihybrid cross, refer to the following link:

https://brainly.com/question/21677243