The ages of bob's children are 3 consecutive integers. the sum of the first integer, the second integer and 2 times the third integer is 25. find the ages
Let x be the age of the first child, then x+1 and x+2 will be the ages of the second and third child respectively x+x+1+2(x+2)=25 4x+5=25 4x=20 x=5 So the ages are 5,6,7
