mrminion21
contestada

Help plz
The ratio of the number of Victor’s tools to the number of Ilya’s tools is 5:2. Victor has 42 more tools than Ilya. How many tools do they have together?

Respuesta :

wolf1728
A) V * (2/5) = I
B) V = I + 42

Substituting A into B
V = (2/5) V + 42
3/5 V = 42
Victor has 70 tools
Ilya has 28 tools

together they have 98 tools


lyndalau86

Answer:

They have 98 tools together

Step-by-step explanation:

  • We are going to call x the number of tools Ilya has.
  • If Victor has 42 more tools than Ilya, then he has x + 42 tools.
  • But we know that the ratio of Victor's tools to Ilya's is 5:2, so the actual number of tools they have must satisfy this radio.

If we write this last paragraph in an equation and solve for x we would get: [tex]\frac{5}{2} =\frac{x+42}{x} \\5x=2(x+42)\\5x=2x+84\\5x-2x=84\\3x=84\\x=28[/tex]

Therefore Ilya has 28 tools and Victor has x+42 = 28 + 42 = 70 tools. And together they have:

70 + 28 = 98 tools.

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