Respuesta :
In order to answer this exercise you need to use the formulas
S = Vo*t + (1/2)*a*t^2
Vf = Vo + at
The data will be given as
Vf = final velocity = ?
Vo = initial velocity = 1.4 m/s
a = acceleration = 0.20 m/s^2
s = displacement = 100m
And now you do the following:
100 = 1.4t + (1/2)*0.2*t^2
t = 25.388s
and
Vf = 1.4 + 0.2(25.388)
Vf = 6.5 m/s
So the answer you are looking for is 6.5 m/s
S = Vo*t + (1/2)*a*t^2
Vf = Vo + at
The data will be given as
Vf = final velocity = ?
Vo = initial velocity = 1.4 m/s
a = acceleration = 0.20 m/s^2
s = displacement = 100m
And now you do the following:
100 = 1.4t + (1/2)*0.2*t^2
t = 25.388s
and
Vf = 1.4 + 0.2(25.388)
Vf = 6.5 m/s
So the answer you are looking for is 6.5 m/s
Answer:
[tex]v_f = 6.48 m/s[/tex]
Explanation:
As we know that her speed while she walk is given as
[tex]v_o = 1.4 m/s[/tex]
now here acceleration is given as
[tex]a = 0.20 m/s^2[/tex]
now the distance moved by her
[tex]d = 100 m[/tex]
now the final speed is given as
[tex]v_f^2 - v_0^2 = 2 a d[/tex]
so we have
[tex]v_f^2 - 1.4^2 = 2(0.20)(100)[/tex]
[tex]v_f = 6.48 m/s[/tex]
