Explanation: Since the two triangles are similar: therefore: AC/CE = BC/CD We are given that: AC = 21 CE = 7 BC = 20-x CD = x Substitute with the givens in the above relation and solve for x as follows: AC/CE = BC/CD 21/7 = (20-x) / x 3 = (20-x)/x 3x = 20-x 3x+x = 20 4x = 20 x = 20/4 x = 5 Now we have: BC = 20-x = 20-5 = 15 CD = x = 5