Respuesta :
We have to find the probability N(11,2)>12, wherein N(11,2)
is the normal law with mean 11 and standard deviation 2.
Using a scientific calculator we get the probability 0.3.
Now multiply by the population which is 1000 like this:
0.3*1000=300.
There is 300 spiders in the colony which weigh more than 12 grams
is the normal law with mean 11 and standard deviation 2.
Using a scientific calculator we get the probability 0.3.
Now multiply by the population which is 1000 like this:
0.3*1000=300.
There is 300 spiders in the colony which weigh more than 12 grams
The probability that a spider selected at a random from the colony weighs more than 12 grams is given by:
[tex]P(x\ \textgreater \ 12)=1-P(x\ \textless \ 12) \\ \\ =1-P\left(z\ \textless \ \frac{x-\mu}{\sigma} \right)=1-P\left(z\ \textless \ \frac{12-11}{2} \right) \\ \\ =1-P(z\ \textless \ 0.5)=1-0.69146=0.30854[/tex]
Thus, given that there are 1000 adult spiders in the colony, the number of spiders in the colony that weigh more than 12 grams is given by 0.30854 * 1000 ≈ 309
[tex]P(x\ \textgreater \ 12)=1-P(x\ \textless \ 12) \\ \\ =1-P\left(z\ \textless \ \frac{x-\mu}{\sigma} \right)=1-P\left(z\ \textless \ \frac{12-11}{2} \right) \\ \\ =1-P(z\ \textless \ 0.5)=1-0.69146=0.30854[/tex]
Thus, given that there are 1000 adult spiders in the colony, the number of spiders in the colony that weigh more than 12 grams is given by 0.30854 * 1000 ≈ 309