You have two windlasses named X and Y. Windlass X drum diameter is 50cm and windlass Y drum diameter is 75cm. Both are hoisting a 50kg weight, Hence, X will lift faster and easier than Y
Generally, the equation for the Torque is mathematically given as
Torque(X)=weight x radius of drum
T=50x9.81x0.25
T=122.625 Nm
For, Torque (Y)
T=50x9.81x0.375
T=183.93 Nm
Generally, the equation for the Equation of Power is mathematically given as
P= Torque * Angular velocity
Angular velocity (w)= 2 x pi x N/60
As a consequence, torque has an inverse relationship to speed. Because of this, the torque will decrease as the speed rises.
According to the previous statement, windlass X has a speed of lift that is at its maximum, but windlass Y has a speed that is very low.
Additionally, power is exactly proportional to torque, which means that the highest possible torque required the highest possible amount of energy and vice versa.
Therefore, X should raise at the highest possible speed while using the least amount of energy.
In conclusion, X will lift faster and easier than Y
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