To answer this question, you need to know the aluminum acetate weight and formula. Molecular weight of aluminum acetate is 204.11g/mol, so the concentration should be: (25.20/204.11 )/(0.185l) = 0.1234 mol/0.185l= 0.6673 M
The aluminum acetate Al(C2H3O2)3 which mean for one aluminum acetate there will be 3 acetate ion. The concentration of acetate should be: 0.6673 M= 2M
