rtrr6039 rtrr6039

14-08-2020
Physics

contestada

g If the momentum of an electron doubles, by what factor would its de Broglie wavelength be multiplied

Respuesta :

Muscardinus Muscardinus

18-08-2020

Explanation:

The de broglie wavelength is given by :

[tex]\lambda=\dfrac{h}{p}[/tex]

Here,

h is Planck's constant

p is momentum

Momentum and De-Broglie wavelength has inverse relationship. If momentum of an electron double, its wavelength gets half.

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