Answer:
The value of the equation for n is [tex]n=\frac{-3A+8}{b-A}[/tex].
Step-by-step explanation:
Consider the provided equation.
[tex]A(n-3)+8=bn[/tex]
We need to solve the equation for n.
Open the parentheses as shown:
[tex]An-3A+8=bn[/tex]
Subtract both the side by An.
[tex]An-An-3A+8=bn-An[/tex]
[tex]-3A+8=bn-An[/tex]
Take n common from right side.
[tex]-3A+8=n(b-A)[/tex]
Divide both the sides by b-A.
[tex]\frac{-3A+8}{b-A}=\frac{n(b-A)}{b-A}[/tex]
[tex]n=\frac{-3A+8}{b-A}[/tex]
Hence, the value of the equation for n is [tex]n=\frac{-3A+8}{b-A}[/tex].
