Weight of block, Wb = mass*gravity = 50*9.8 = 490 N
Since block is being pulled up by a 13-degree slope
Therefore, Force which is acting parallel to the slop:
F p =490 Sin [tex] 13^{0} [/tex]= 110.2N
Force which is acting perpendicular to the slope:
Fv =490 Cos[tex] 13^{0} [/tex] = 477.4 N
Net force can be given as follows:
F n = (250 - 110.2 - 0.2*477.4) N
Fn=44.3N
Now acceleration is given by the ratio of force to mass
a = Fn/m
=44.3/50 = 0.89 ms^-2
