The work of a student to solve a set of equations is shown:

Equation 1: m = 8 + 2n
Equation 2: 3m = 4 + 4n

Step 1:
−3(m) = −3(8 + 2n) [Equation 1 is multiplied by −3.]
3m = 4 + 4n [Equation 2]

Step 2:
−3m = −24 − 6n [Equation 1 in Step 1 is simplified.]
3m = 4 + 4n [Equation 2]

Step 3:
−3m + 3m = −24 − 6n + 4n [Equations in Step 2 are added.]

Step 4:
0 = −24 − 2n

Step 5:
n = −12

In which step did the student first make an error?

Step 4

Step 3

Step 2

Step 1

To create an equation in one variable using the elimination method, you can either add or subtract the equations. To eliminate a variable, add the equations when the coefficients of one variable are in opposition, and subtract the equations when the coefficients of one variable are in equality.

How to solve this problem?

Notice that the student uses the elimination method to solve the equations. In Step 1, he makes the coefficients of m equal in both equations. In Step 2, he simplifies the previous step. In Step 3, he wants to add both equations to create an equation in one variable. But He forgot to add 4 of Equation 2. It's a mistake.

Therefore the student first makes an error in the Step 3 where he adds equations in Step 2 to use the elimination method.

Know more about the elimination method here -

https://brainly.com/question/3472533

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