Respuesta :

2HNO₃ + Ba(OH)₂ = Ba(NO₃)₂ + 2H₂O

2 mol HNO₃ - 1 mol Ba(OH)₂
x mol HNO₃ - 2.50×10⁻² mol Ba(OH)₂

x=2.50×10⁻²×2/1=0.05 mol

The number of mole of HNO₃ present if 2.50×10¯² mole of Ba(OH)₂ is required to neutralize the acid is 5×10¯² mole

We'll begin by writing the balanced equation for the reaction. This is given below:

Ba(OH)₂ + 2HNO₃ —> Ba(NO₃)₂ + 2H₂O

From the balanced equation above,

1 mole of Ba(OH)₂ required 2 moles of HNO₃.

With the above information, we can obtain the number of mole of HNO₃ required to neutralize 2.50×10¯² mole of Ba(OH)₂. This can be obtained as follow:

From the balanced equation above,

1 mole of Ba(OH)₂ required 2 moles of HNO₃.

Therefore,

2.50×10¯² mole of Ba(OH)₂ will require = 2.50×10¯² × 2 = 5×10¯² mole of HNO₃

Thus, 5×10¯² mole of HNO₃ is required to neutralize 2.50×10¯² mole of Ba(OH)₂.

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