Answer:
21.456 kJ/h
Explanation:
See the figure attached. In this case
[tex]W_{cycle} = 4 kW [/tex]
[tex]Q_{out} = \text{heating effect}[/tex]
Coefficient of performance in heat pump is defined by
[tex]COP = \frac{Q_{out}}{W_{cycle}} [/tex]
[tex]Q_{out} =COP*W_{cycle} [/tex]
[tex]Q_{out} =1.49*4 \, W [/tex]
[tex]Q_{out} = 5.96 \, W [/tex]
Now it is necessary to change units, remember that Watt (W) is defined as J/s
[tex]Q_{out} = 5.96 \frac{J}{s} \frac{3600s}{1 h} \frac{1 kJ}{1000 J}[/tex]
[tex]Q_{out} = 21.456 \frac{kJ}{h} [/tex]
