A boat takes off from the dock at 2.5 m/s and speeds up at 4.2 m/s2 for 6.0 s. How far has the boat traveled? Round your answer to the nearest whole number.

Respuesta :

it's simple bro
91m is the answer

Lanuel

The displacement of the boat is 91 meters.

Given the following data:

  • Initial velocity = 2.5 m/s
  • Acceleration = [tex]4.2 m/s^2[/tex]
  • Time = 6.0 seconds

To find the displacement of the boat, we  would use the second equation of motion.

Mathematically, the second equation of motion is given by the formula;

[tex]S = ut + \frac{1}{2}at^2[/tex]

Where:

  • S is the displacement or distance covered.
  • u is the initial velocity.
  • a is the acceleration.
  • t is the time measured in seconds.

Substituting the values into the formula, we have;

[tex]S = 2.5(6) + \frac{1}{2}(4.2)(6)^2\\\\S = 15 + 2.1(36)\\\\S = 15 + 75.6\\\\S = 90.6[/tex]

Displacement, S = 91 meters.

Therefore, the displacement of the boat is 91 meters.

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