You place a bet on the number 21 in roulette. The probability of winning is 1 38 , and the company hosting the casino night for a city fundraiser gives the payoff odds as 35:1. What are the odds that the ball will land on the number 21?


1:21


1:38


1:37


1:35

Respuesta :

Answer-

The odds that the ball will land on the number 21 is 1:37 .

Hint-

Definition of odds-

Odd is expressed as the ratio of number of favorable events to the number of unfavorable events.

Definition of probability-

Probability is expressed as the ratio of the number of events favorable to a specific event, to the total number of events.

Solution-

If A is the event of landing of ball on 21, then given that

[tex]P(A)=\frac{1}{38}[/tex]

Here, it is the favorable event.

The probability of not landing on 21 is,

[tex]P({A}')=1-P(A)=1-\frac{1}{38}=\frac{37}{38}[/tex]

Here, it is the unfavorable event.

Now,

Odds that the ball will land on the number 21 =

                               [tex]\frac{P(A)}{P({A}')}[/tex]

                               [tex]\frac{\frac{1}{38}}{\frac{37}{38}} =\frac{1}{37} = 1:37[/tex]

Answer: 1:37

Step-by-step explanation:

Winning probability/losing probability = 1/38 divided by 37/38; look at the numerators and that your answer which is 1:37

Just in case I got the 37/38 from the knowing there was only one winner from 38 people therefore the rest are losers (37)