Reggie can run 330 feet in 30 seconds.
Which shows Reggies rate of speed?

A. 330ft/1sec

B.30ft/1sec

C.330ft/30sec

D.30ft/330sex

Respuesta :

aachen

Answer:

[tex]v=\dfrac{330\ ft}{30\ s}[/tex]

Step-by-step explanation:

It is given that,

Distance covered by Reggie, d = 330 feet

Time taken by Reggie, t = 30 seconds

Let v is the speed of the Reggie. It can be calculated by dividing total distance by total time taken during entire journey. Mathematically, it is given by :

[tex]v=\dfrac{d}{t}[/tex]

[tex]v=\dfrac{330\ ft}{30\ s}[/tex]

v = 11 m/s

So, the Reggie rate of speed is [tex]\dfrac{330\ ft}{30\ s}[/tex]. Hence, the correct option is (c).

Answer:C.330ft/30sec

Step-by-step explanation:

t is given that,

Distance covered by Reggie, d = 330 feet

Time taken by Reggie, t = 30 seconds

Let v is the speed of the Reggie. It can be calculated by dividing total distance by total time taken during entire journey. Mathematically, it is given by :

v = 11 m/s

So, the Reggie rate of speed is . Hence, the correct option is (c).