Respuesta :
you can solve this by factoring left side into perfect square.
[tex](x-5)^2 = 35[/tex]
Now take square root, remember to include plus-minus
[tex]x - 5 = \pm \sqrt{35} \\ \\ x = 5 \pm \sqrt{35}[/tex]
[tex](x-5)^2 = 35[/tex]
Now take square root, remember to include plus-minus
[tex]x - 5 = \pm \sqrt{35} \\ \\ x = 5 \pm \sqrt{35}[/tex]
Answer:
x1,2 and x1 = -rad35 + 5 and x2 that is +rad35 + 5
Step-by-step explanation: