Respuesta :
B for Brats and H for Hamburgers
3 total for each of 30 guests
B + H = 3x30 = 90
Then $1.25B + $0.75H <= to $120
Solving for B=90-H
1.25B + 0.75(90-B) <=120 yields cost of B is $52.50 so B = 42.
90-42 = 48 H
So you can buy 42 Brats and 48 Hamburgers
3 total for each of 30 guests
B + H = 3x30 = 90
Then $1.25B + $0.75H <= to $120
Solving for B=90-H
1.25B + 0.75(90-B) <=120 yields cost of B is $52.50 so B = 42.
90-42 = 48 H
So you can buy 42 Brats and 48 Hamburgers
Answer:
x + y ≥ 90 --------(1)
1.25x + 0.75y ≤ 120 ---------(2)
Step-by-step explanation:
You are serving bratwurst and hamburgers at your annual picnic.
We will make first equation by this statement "You want at least 3 bratwurst and hamburgers for each of your 30 guest."
x + y ≥ (30×3)
x + y ≥ 90 --------(1)
Let x be the number of bratwursts and y the number of hamburgers.
The second equation is made by the statement "Bratwurst cost $1.25 each and hamburgers $0.75 each and your budget is $120."
1.25x + 0.75y ≤ 120 ---------(2)