let's say the sides are "a" first one, "b" second one and "c" the third one
ok, let's say the shortest is "a"
and let's say "b" is -> " twice the length of the shortest side"
so b = 2a
and let's say "c" is -> "3rd side 14 more feet than length of shortest side"
so c = a + 14
we know the perimeter ( sum of all sides ) is 154
[tex]\bf \begin{array}{llll}
a&b&c\\
&\downarrow&\downarrow \\
&2a&a+14\\
\downarrow &\downarrow &\downarrow \\
\end{array}\\
\ a+b+\ c=154\\\\
a+(2a)+(a+14)=154[/tex]
solve for "a"
