Respuesta :
[tex](x-a)^2+(y-b)^2=r^2[/tex]
[tex]x^2 + y^2 - 10x + 6y + 18 = 0\\\\ x^2-10x+y^2+6y+18=0 \\\\ (x-5)^2-25+(y+3)^2-9+18=0\\\\ (x-5)^2+(y+3)^2=16\\\\ r^2=16[/tex]
[tex]r = \sqrt{16} \\\\ r=4[/tex]
[tex]x^2 + y^2 - 10x + 6y + 18 = 0\\\\ x^2-10x+y^2+6y+18=0 \\\\ (x-5)^2-25+(y+3)^2-9+18=0\\\\ (x-5)^2+(y+3)^2=16\\\\ r^2=16[/tex]
[tex]r = \sqrt{16} \\\\ r=4[/tex]