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When 4.008 g of sulfur is burned completely in abundant air, it combines with oxygen to form a single gaseous product with a total mass of 10.008 g. The mass percent of sulfur in the product is % (2 dec places). The mass percent of oxygen in the product is % (2 dec places).

Respuesta :

Answer: The mass percent of sulfur and oxygen in the compound is 40.05 % and 59.95 % respectively

Explanation:

To calculate the mass percentage of element, we use the equation:

[tex]\text{Mass percent of element}=\frac{\text{Mass of element}}{\text{Mass of compound}}\times 100[/tex]

  • For sulfur:

Mass of sulfur = 4.008 g

Mass of compound = 10.008 g

Putting values in above equation, we get:

[tex]\text{Mass percent of sulfur}=\frac{4.008g}{10.008g}\times 100=40.05\%[/tex]

  • For oxygen:

Mass of oxygen = [10.008 - 4.008] = 6 g

Mass of compound = 10.008 g

Putting values in above equation, we get:

[tex]\text{Mass percent of oxygen}=\frac{6g}{10.008g}\times 100=59.95\%[/tex]

Hence, the mass percent of sulfur and oxygen in the compound is 40.05 % and 59.95 %

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