The force due to gravity on the satellite when its distance from the earth's center is 3d is ; 1/9 F₁
Given data :
Initial distance of a satellite from the center of the earth = d
Initial force due to gravity on the satellite = F₁
Final distance of the satellite from the center of the earth = 3d
Final force due to gravity on the satellite ( F₂ ) = ?
applying the relation below
F₁ = K / d² ----- ( 1 ) where K = constant
F₂ = K / (3d)² --- ( 2 ).
Next step ; Divide equation ( 1 ) by equation ( 2 )
F₁ / F₂ = 3²
= 9
∴ F₂ = 1/9 F₁
Hence Inconclusion the force due to gravity on the satellite when its distance from the earth's center is 3d is ; 1/9 F₁
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