Answer: The moles of Ag produced will be 11.02 moles.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
For copper:
Given mass of copper = 350 g
Molar mass of copper = 63.5 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of copper}=\frac{350g}{63.5g/mol}=5.51mol[/tex]
For the given chemical equation:
[tex]Cu(s)+2AgNO_3(aq.)\rightarrow 2Ag(s)+Cu(NO_3)_2(aq.)[/tex]
Silver nitrate is present in excess, so it is considered as an excess reagent and copper is considered as a limiting reagent because it limits the formation of products.
By Stoichiometry of the reaction:
1 mole of copper produces 2 moles of silver.
So, 5.51 moles of copper will produce = [tex]\frac{2}{1}\times 5.51=11.02mol[/tex] of silver.
Thus, the moles of Ag produced will be 11.02 moles.
