Answer: The magnitude and direction of the vector with component (6, 2) after multiplication with scalar value 3 is:
magnitude: 19.0; direction: 18.4°
Explanation;
[tex]\overrightarrow{V}=6\widehat{i}+2\widehat{j}[/tex]
[tex]|\overrightarrow{V}|=\sqrt{6^2+2^2}=2\sqrt{10}[/tex]
[tex]\overrightarrow{V}=3\times |\overrightarrow{V}|=3\times 2sqrt{10}=18.97\approx 19[/tex]
Direction:[tex]\tan\theta =\frac{2}{6}p[/tex]
[tex]\theta =\tan^{-1}\frac{1}{3}=18.43^o\approx 18.4^o[/tex]
The magnitude and direction of the vector with component (6, 2) after multiplication with scalar value 3 is:
magnitude: 19.0; direction: 18.4°
