Vertical component of velocity = 16sin(30°) = 8m/s
at the highest point of flight, the velocity of the ball is 0 (that moment when it stops before starting to fall) so:
[tex]v^2=u^2+2as[/tex]
[tex]0^2=8^2+(2\times-9.81\times s)[/tex]
[tex]s= \frac{0^2-8^2}{2\times-9.81} [/tex]
s=3.26m
So rounding up gives option B. (3.3m)
