Answer:
Step-by-step explanation:
they want to know a point on the line... that has a gradient ( think slope ) of -1/3 and has the point of (-2,5) on it. So find the formula for that line
with the point slope formula y-y1 = m(x - x1)
plug in what we know
y - 5 = - 1/3 (x -(-2))
y - 5 = -1/3(x+2)
y - 5 = -1/3x - 2/3
y = - 1/3x - 2/3 + 5
y = - 1/3x + 4 1/3
y = -1/3x + 13 / 3
Now use your formula to find any new point plug in 1 for x ( b/c it's easy)
y = 12/3 when x= 1. so ( 1, 4 ) is another point on the line :)
don't forget to show your work :P
