Answer:
[tex]\huge\boxed{\sf g_2 = 12\ feet}[/tex]
Step-by-step explanation:
24, g₂, 6, .....
Since the pattern in decreasing geometrically, we will use the formula:
[tex]a_n=ar^{n-1}[/tex]
Where,
n = position of the term
[tex]a_n[/tex] = nth term
a = 1st term
r = common ratio (ratio of second to first term)
First, we'll find r.
[tex]a_3[/tex] = 6
a = 24
n = 3
r = ?
So,
[tex]\displaystyle a_3=(24)(r)^{3-1}\\\\6 = 24(r^2)\\\\Divide \ both \ sides \ by \ 24\\\\\frac{6}{24} = r^2\\\\\frac{1}{4} = r^2\\\\Take \ square \ root \ on \ both \ sides\\\\\frac{1}{2} = r\\\\r = \frac{1}{2}[/tex]
Now, to find the second term, we will have to multiply r with the first term.
So,
g₂ = (24) × (1/2)
[tex]\rule[225]{224}{2}[/tex]