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60 POINTS PLEASE HELP ITS URGENT 1. Write a quadratic equation that can be solved by factoring. Solve your equation and show and explain all your work. 2. In this unit you have learned about several different ways to solve quadratic equations. How do you determine which method to use when you’re trying to solve a quadratic equation?

Respuesta :

you have a quadratic equation that can be factored, like x2+5x+6=0.This can be factored into(x+2)(x+3)=0.

So the solutions are x=-2 and x=-3.

2. 

1. Try first to solve the equation by factoring.  Be sure that your equation is in standard form (ax2+bx+c=0) before you start your factoring attempt.  Don't waste a lot of time trying to factor your equation; if you can't get it factored in less than 60 seconds, move on to another method.
2. Next, look at the side of the equation containing the variable.  Is that side a perfect square?  If it is, then you can solve the equation by taking the square root of both sides of the equation.  Don't forget to include a ± sign in your equation once you have taken the square root.
3.
Next, if the coefficient of the squared term is 1 and the coefficient of the linear (middle) term is even, completing the square is a good method to use.
4.Finally, the quadratic formula will work on any quadratic equation.  However, if using the formula results in awkwardly large numbers under the radical sign, another method of solving may be a better choice.
Step 1: try to solve the equation by factoring. Be sure that your equation is in standard form (ax^2+bx+c=0) before you start your factoring attempt.
Step 2: look at the side of the equation containing the variable. Is that side a perfect square? if it is then you can solve the equation by taking the square root of both sides of the equation. Don't forget the plus and minus sign in your equation once you have taken the square root
Step 3: If the coefficient of the squared term is 1 and the coefficient of the middle terms even completing the square is a good method to use.
Step 4: The quadratic formula will work on any quadratic equation. If using the formula results in awkwardly large numbers under the radical sign another method of solving may be a better choice.