The equation of a circle is (x – 3)2 +(+8)2 = 36. Relative to the standard equation of a circle (zº+y? = r?), how has
this circle been shifted? What is the radius of the circle?
A. The circle has been shifted 3 units to the right and 8 units down.
= 6
B. The circle has been shifted 3 units to the left and 8 units down.
r=6
C. The circle has been shifted 8 units to the left and 3 units up.
r = 36
D. The circle has been shifted 3 units to the left and 8 units up.
r = 36
Please select the best answer from the choices provided
A
B

Respuesta :

Answer:

A. The circle has been shifted 3 units to the right and 8 units down, r=6

Step-by-step explanation:

Recall that the equation of a circle is [tex](x-h)^2+(y-k)^2=r^2[/tex] where [tex](h,k)[/tex] is the center of the circle and [tex]r[/tex] is the radius.

Given that the equation is [tex](x-3)^2+(y+8)^2=36[/tex], this tells us that the center of the circle is at [tex](h,k)\rightarrow(3,-8)[/tex] and the radius is [tex]r=6[/tex]. Since the value of [tex]h[/tex] represents the amount of horizontal shift from the origin and [tex]k[/tex] represents the amount of vertical shift from the origin, then the circle was shifted 3 units to the right and 8 units down.