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[tex]\displaystyle\\ \frac{3y-8}{12} = \frac{y}{5} \\ \\ 5(3y-8)=12y\\\\ 15y-40=12y\\\\ 3y = 40\\\\ \boxed{y = \frac{40}{3}} [/tex]



Answer:

The solution to the proportion [tex]\frac{3y-8}{12}=\frac{y}{5}[/tex] is [tex]y=\frac{40}{3}[/tex]

Step-by-step explanation:

Given  proportion [tex]\frac{3y-8}{12}=\frac{y}{5}[/tex]

WE have to find the solution for the given proportion.

Consider the given proportion [tex]\frac{3y-8}{12}=\frac{y}{5}[/tex].

Cross multiply the terms, we get,

5 (3y - 8) = 12( y )

Simply the terms by multiplying 5 by each term in brackets, we get,

15y - 40 = 12y

taking y terms one sides, we get,

15y - 12y = 40

On simplifying , we get,

3y = 40

Divide both side by 3, we have,

[tex]y=\frac{40}{3}[/tex]

Thus, the solution to the proportion [tex]\frac{3y-8}{12}=\frac{y}{5}[/tex] is [tex]y=\frac{40}{3}[/tex]