Respuesta :
[tex]\displaystyle\\ \frac{3y-8}{12} = \frac{y}{5} \\ \\ 5(3y-8)=12y\\\\ 15y-40=12y\\\\ 3y = 40\\\\ \boxed{y = \frac{40}{3}} [/tex]
Answer:
The solution to the proportion [tex]\frac{3y-8}{12}=\frac{y}{5}[/tex] is [tex]y=\frac{40}{3}[/tex]
Step-by-step explanation:
Given proportion [tex]\frac{3y-8}{12}=\frac{y}{5}[/tex]
WE have to find the solution for the given proportion.
Consider the given proportion [tex]\frac{3y-8}{12}=\frac{y}{5}[/tex].
Cross multiply the terms, we get,
5 (3y - 8) = 12( y )
Simply the terms by multiplying 5 by each term in brackets, we get,
15y - 40 = 12y
taking y terms one sides, we get,
15y - 12y = 40
On simplifying , we get,
3y = 40
Divide both side by 3, we have,
[tex]y=\frac{40}{3}[/tex]
Thus, the solution to the proportion [tex]\frac{3y-8}{12}=\frac{y}{5}[/tex] is [tex]y=\frac{40}{3}[/tex]