The derivate of the logarithmic function is :
f'(x) = [(4*x^3 + 2*e^2x)/(x^4 + e^2x)]
How to find f'(x)?
Remember that for the natural logarithm g(x) = ln(x), we have:
dg/dx = 1/x
Here we have the function:
f(x) = ln(x^4 + e^2x).
The derivate will be one over the argument (for what we wrote above) times the derivate of the argument, we will get:
f'(x) = [1/(x^4 + e^2x)]*(4*x^3 + 2*e^2x)
Learn more about logarithmic functions:
https://brainly.com/question/13473114
#SPJ1
