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consider a uniformly charged ring in the xy plane, centered at the origin. the ring has radius a and positive charge q distributed evenly along its circumference. (figure 1)

Respuesta :

The correct answer is Ez = kqz / (z^2+a^2)^3/2

The expression of the electric field is,

E=kq / r^2

Here, r is the distance and its value is √z²+a²

Substituting the value of r in the above expression.

E = kq / (√z²+a²)^2

The expression of the electric field along the z-direction is given by,

dEz=dEcos

Here, the value of the cosine function is z / √z²+a²

On integrating the above expression and substituting the value

Ez = Ecosθ

Ez = kq / √z²+a²^2 *  z / √z²+a²

Ez = kqz / (z^2+a^2)^3/2

What is an electric field?

  • An electric field (sometimes E-field) is a physical field that surrounds electrically charged particles and exerts a force on all other charged particles in the field, either attracting or repelling them.
  • It also applies to the physical field for a system of charged particles.

To know more about electric field, click the link given below:

https://brainly.com/question/26446532

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