Respuesta :
just after the switch is closed,
the inductor will act like open circuit
so
current in the loop=24/(72+72+57+78)=86 mA
(1.) the magnitude of the current through the resistor R1just after the switch is closed=86 mA
(2.) after very long time,
inductor will act as short circuit.
so current through R2 and R3 are zero.
current through R1 and R4 =24/(72+78)=160 mA
the magnitude of the current that flows through the resistor R1a very long time after the switch has been closed=160 mA
(3.) the magnitude of the voltage across the inductor just after the switch is closed=i*(R2+R3)=0.086*(72+57)=11.094 volts
(4.) the magnitude of the current through the inductor after the switch has been closed for a very long time=the magnitude of the current that flows through the resistor R1a very long time after the switch has been closed=160 mA
(5) the magnitude of the current through the resistor R2just after the switch is closed=86 mA.
To learn more about the circuit the link is given below:
https://brainly.com/question/1695461?
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